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Make the minimum total +1 increments so every subarray of length ≥3 has max ≥ k — equivalently, choose indices to raise to at least k such that every consecutive triple contains at least one chosen index, minimizing the sum of required increments. This becomes a costed interval-cover/DP optimization: pick positions to cover all length-3 windows at minimum total upgrade cost.
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Leetcode 2919. Minimum Increment Operations to Make Array Beautiful
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Source snapshot: Nov 12, 2026
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