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Given a target word and a dictionary, find the shortest abbreviation (letters kept + counts for omitted runs) of the target that cannot represent any dictionary word; this reduces to selecting positions to keep so that for every same-length dictionary word at least one kept position differs, solvable by filtering same-length words and searching bitmask patterns (with bit operations/pruning) for the minimum-length distinguishing mask.
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Leetcode 411. Minimum Unique Word Abbreviation
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Source snapshot: Nov 12, 2026
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